WebMar 29, 2024 · Transcript. Example 5 Determine the AP whose 3rd term is 5 and the 7th term is 9. We know that an = a + (n – 1)d From (1) & (2) 5 – 2d = 9 – 6d 6d – 2d = 9 – 5 Given 3rd term is 5 a3 = a + (3 – 1)d 5 = a + 2d a = 5 – 2d Given 7th term is 9 a7 = a + … WebQuestion : Determine the AP whose third term is 16 and 7th term exceeds 5th term by 12. Let a be the first term, a3 be the third term , a5 be the fifth term and a7 be the seventh term. a7 = a5 + 12.. (1) a7 = 2d... (2) Hence, The AP is 4, 10, 16.. We're not given the value of the 7th term. To make our calculations and our answer simple, we need ...
Determine the AP whose third term is 16 and the 7th term
WebMar 3, 2024 · In the following APs, find the missing term in the boxes (i) 2, , 26 Solution : Given: first term (a) = 2 third term (a3) = 26 a 3 can be calculated using the formula a n = a + (n – 1)d a 3 = 2 + (3 – 1) * d 26 = 2 + 2d 24 = 2d d = 12 So a 2 can be calculated using the formula a n = a + (n – 1)d a 2 = 2 + (2 – 1) * 12 a 2 = 2 + 12 a 2 = 14 WebThird term of A.P., A 3 = 16. ⇒ a + (3-1) d = 16. ⇒ a + 2 d = 16 … (1) Seventh term of A.P., A 7 = a + (7-1) d = a + 6 d. Fifth term of A.P., A 5 = a + (5-1) d = a + 4 d. It is given that the 7 t h term exceeds the 5 t h term by 12. ⇒ A 7-A 5 = 12. ⇒ a + 6 d-(a + 4 d) = … how to size a step down transformer
Determine the AP whose third term is 16 and the7th term
WebMar 23, 2024 · Determine the A.P. whose 3rd term is 16 and the 7th term exceeds the 5th term by 12. Last updated date: 23rd Mar 2024 ... If each term of an AP is increased, decreased, multiplied or divided by the same non-zero constant, the resulting sequence also will be in AP. In an AP, the sum of terms equidistant from beginning and end will be … WebSolution Given: 3rd term of the AP is 16. a 3 = 16 a + (3 − 1)d = 16 a + 2d = 16 ..... (1) Also, 7th term exceeds the 5th term by 12. a 7 − a 5 = 12 [ a+ (7 − 1)d ] − [a + (5 − 1)d] = 12 (a + 6d) − (a + 4d) = 12 2d = 12 d = 6 From equation (1), we obtain a + 2 (6) = 16 a + 12 = 16 … WebApr 25, 2024 · Determine the AP whose third term is 16 and the 7th term exceeds the 5th term by 12. arithmetic progression ncert class 10 maths cbse 1 Answer +1 vote answered May 8, 2024 by sarthaks (29.7k points) selected Dec 11, 2024 by Vikash Kumar Best answer Solution: We have given a3 = 16 a + (3 − 1) d = 16 a + 2d = 16 (1) a7 − a5 = 12 how to size a standing rib roast